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-   -   Factoring completely (https://www.askmehelpdesk.com/showthread.php?t=342770)

  • Apr 17, 2009, 12:17 PM
    iruleqwerty1234
    Factoring completely
    What's 9k power of 2 minus 12k plus 4
  • Apr 17, 2009, 12:19 PM
    iruleqwerty1234
    Factoring completely
    12a(2)b(2)-27a(2)

    IN THE BRACKETS ARE THE POWERS
  • Apr 17, 2009, 08:11 PM
    Unknown008

    Ok, here's your question:



    Give the factors of +4 (this is like trial and error)
    They are +1, +2, +4 but also -1, -2, -4.

    Now, factors of 9, which are +1, +3, +9 (no need to find negative factors here)

    Write them in a certain form, like for example this one;

    OOOOOO
    OOOOOOOOOOOOO
    OOOOOOOOOOOOOOOOOO
    OOOOOOOOOOOOOOOO

    You obtain +13k when you add the products of 9k and +1, and k and +4. You need to obtain -12k.

    By trying different numbers, you'll see that the answer is from;

    OOOOOO
    OOOOOOOOOOOO
    OOOOOOOOOOOOOOOOOO
    OOOOOOOOOOOOOOOO

    And you factors will be

    I know this may be a little confusing, there are several methods, and that's the one I was taught. Post back if you don't understand.
  • Apr 17, 2009, 08:23 PM
    Unknown008
    Quote:

    Originally Posted by iruleqwerty1234 View Post
    12a(2)b(2)-27a(2)

    IN THE BRACKETS ARE THE POWERS

    Here's your question;



    That's more simple than the previous one;

    what are the common factors in and ?

    You'll find them be , so factorise by that term and put what remains into brackets;



    You'll find your original question if you expand. Now, it happens that the terms in brackets are perfect squares, 4, and 9. From your formula of , further factorise to give;


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