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The area is 0.7858 square inches. Convert that to square feet.

$0.7858\,in^2\,(\frac {0.00694\,ft^2}{in^2} = 0.00546\,ft^2)$

The flow is 4 gallons/minute. Convert that to cubic feet per minute

$(\frac {4\,gal}{min})(\frac {0.13368<br /> ,ft^3}{gal})\,=\,0.535\,\frac {ft^3}{min}$

Now, notice how the units work:

$\frac {(\frac {ft^3}{min})}{ft^2}\,=\,\frac {ft}{min}$

So simply divide

$\frac {(\frac {0.535\,ft^3}{min})}{0.00546\,ft^2}\,=\,\frac {97.99\,ft}{min}$

It looks like it's darn close to 98 ft/min.