Solving a word problem using a system of linear equations:
A motorboat travels in 456kkm/8 hr hours going upstream and in 534 km in 6 hours going downstream. What is the speed of the boat in still water, and what is the speed of the current?

Let =the speed of the boat and equal the speed of the current.

Since d=rt.

When the boat is going upstream it is going against the current, so the rate is



Going downstream it is





Solve for the two rates.

Hello mattiewal

Call the real speed of boat a, call speed of water current b.
Total distance travelled = travel speed times time.
The travel speed is real boat speed + or - speed of current.

456 = 8(a - b) --> 456/8 = .a - b --> 57 = a - b
534 = 6(a + b) --> 534/6 = a + b --> 89 = a + b

Add together to eliminate b and solve a (real boat speed). Than solve b (current speed).
Note that both a and b are in Km/hr.

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A local hamburger shop sold a combined total of hamburgers and cheeseburgers on Sunday. There were fewer cheeseburgers sold than hamburgers. How many hamburgers were sold on Sunday?

A local hamburger shop sold a combined total of hamburgers and cheeseburgers on Sunday. There were fewer cheeseburgers sold than hamburgers. How many hamburgers were sold on Sunday?