Edited. If you are curious as to what this post said, please scroll down to the link below.

1 out of 3

Anybody else? And if you could explain why, I would love to hear it.

Woops, I meant to say your answer is incorrect, and that the correct answer is C, but I was going to give you props anyway. :)

It doesn't matter if they reveal a "goat door" or not, and doesn't matter if the member switches.

There are always three doors, and always only one car.

The only possible arrangements are

1 2 3
G g c
G c g
C g g

That's it... now look down vertically... if you choose ANY door, you will always have a 1 in 3 chance.

Actually, I was wrong and I get it.

Ill explain...

assuming

1 2 3
g g c
g c g
c g g

if I choose door 1, scenario 1 ( g g c)... they'll show me door 2 and I, by your rules, must switch to 3 = car

if I choose door 1, scenario 2 (g c g)... they'll show me door 3 and I must switch to 2 = car

if I choose door 1, scenario 3 (c g g)... they'll show me door 2 or 3, and ill switch to a goat door = no car.

so choosing door one, with a goat door revealed, and a mandated switch (what I ignored at first) will get me a car in 2 or 3 tries.

same goes for any other door chosen.

my mistake was ignoring the mandated switch.

This is known as the Monty Hall problem.

See here:

Monty Hall problem - Wikipedia, the free encyclopedia

Woot! Ty kp2171! I appreciate your efforts greatly!

galactus is correct. Thanks for the link!