Find the equation of the line tangent to the graph of h(x)=5x^(3)-10x^(2)+20 at x=2 (answer has to be in slope intercept form)

Slope intercept form is y=mx+b.

You are given x. For y, plug x=2 into h(x).

To find m, differentiate h(x) and plug in x=2. Then, you have the slope at that point.

Plug all this into y=mx+b and solve for b. You're done.