When ax^3 - 4x^2 + 5x - 3 is divided by (x +2) and (x-1), the remainders are equal. Find a.
I am unsure of this answer I worked out the remainder to be a = -3
But when I substitute it into the equation they do not match
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When ax^3 - 4x^2 + 5x - 3 is divided by (x +2) and (x-1), the remainders are equal. Find a.
I am unsure of this answer I worked out the remainder to be a = -3
But when I substitute it into the equation they do not match
I think you have the right answer. I divided -3x^3-4x^2+5x -3 by x+2 and also by x-1 and both times got a remainder of -5.
Here's a way to look at it if you like.
Dividing the given cubic by x-1 gives a remainder of
Dividing by x+2 gives a remainder of
and -5 is indeed the remainder.
Check.
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