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-   -   The Remainder Theorem working out 2 factors (https://www.askmehelpdesk.com/showthread.php?t=324456)

  • Mar 3, 2009, 12:05 PM
    rickjosh19
    The Remainder Theorem working out 2 factors
    When ax^3 - 4x^2 + 5x - 3 is divided by (x +2) and (x-1), the remainders are equal. Find a.

    I am unsure of this answer I worked out the remainder to be a = -3

    But when I substitute it into the equation they do not match
  • Mar 3, 2009, 12:53 PM
    ebaines

    I think you have the right answer. I divided -3x^3-4x^2+5x -3 by x+2 and also by x-1 and both times got a remainder of -5.
  • Mar 3, 2009, 01:08 PM
    galactus
    Here's a way to look at it if you like.

    Dividing the given cubic by x-1 gives a remainder of

    Dividing by x+2 gives a remainder of



    and -5 is indeed the remainder.

    Check.

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