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What is the answer to this radcal expression

square root of X^8 over 81Y^7

Is that $\sqrt{\frac{x^{8}}{81y^{7}}}$ or $\frac{\sqrt{x^{8}}}{81y^{7}}$ ?

I assume the former?

Then, use the exponent laws. Remember, the exponents of exponents multiply.

$\left(\frac{x^{8}}{81y^{7}}\right)^{\frac{1}{2}}$

8 times 1/2 is 4, so we have in the numerator: $x^{4}$

In the denominator, what's the square root of 81? What is 7 times 1/2?

Can you get it now?

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