I've been spending the last 3 or so hours on this problem and I cannot figure it out!
5x^3=5x^2+12x
I subtract the 5x^3 to get it on one side so that it equals to zero. Now when I take out the GCF of x it leaves me with x(-5x^2+5x+12) and from there I have no idea... You can't multiply 12 and negative 5 and find somethat when when multipied =-60 but when added get 5. When I do the quadratic Formula I end up getting something like 2i square root 43 and I'm not sure that sounds right since I need 3 answers seeing as how the highest exponet is 3