Find two consecutive even numbers whose sum is 1998

take 2n as even number, then 2n + 2 as the next even number

2n + (2n+2) = 1998

solve for n, and then find out what 2n is. That's your even number. 2n + 2 is your consecutive even.

Too easy, Is this a test to be a Math Teacher?
Engineer? Hope not. 998,1000

1998/2 = 999

answer = 999 - 1 = 998
answer = 999 + 1 = 1000

998 + 1000 = 1998