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-   -   Finding roots of a quadratic equation (https://www.askmehelpdesk.com/showthread.php?t=298596)

  • Jan 3, 2009, 12:38 PM
    Canucks16
    Finding roots of a quadratic equation
    I need to know how to find the roots of a quadratic. For example 5x^-4x=9x+6

    a walkthrough of the qestion would be fantastic
  • Jan 3, 2009, 04:03 PM
    v1033

    5x^-4x=9x+6

    well the first thing to do is get everything onto one side so the quadratic =0

    5x^-13x-6=0

    then we need to factorise the equation so we think about the coeffiecents

    5 is prime so we start our brackets

    (5x ? )(x ? )=0

    6 = 2x3 or 1x6 and we need -6 so we will have a - somewhere

    15 = 3x5 - 2x1 so

    5x^-13x-6=(5x+2)(x-3)

    (5x+2)(x-3)=0 so 5x+2=0 or x-3=0

    so x=3 or x=-2/5

    let me know if you need further clarification
  • Jan 3, 2009, 04:44 PM
    Canucks16

    That's great thanks
  • Jan 4, 2009, 09:09 AM
    EuRa

    Yeah that or the Quadratic formula.

    -B ± √ ( B² - 4AC)
    _________________

    2A


    Where A B and C = Ax² + Bx + C

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