Suppose you roll 4 dice.

a) What is the probability that you get 4 different numbers?

b) What is the probability that you get '2 pairs' (two of one number and
two of another number?)

c) Now suppose that you continue rolling 4 dice over and over until you get
either get '4 different numbers' or 'two pairs'. What is the probability
that you get 'two pairs' first?

Dear xotica

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Quote:

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b) What is the probability that you get '2 pairs' (two of one number and
two of another number?)

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Count them up. Let's pair them.

1122, 1133,1144,1155,1166,2233,2244,2255,2266,3344,3355, 3366,4455,4466,5566

Each of these can be arranged in 6 ways.

(15)(6)=90

There are total arrangements.

Does anyone know c?