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  • Nov 2, 2008, 01:00 PM
    cqaetars
    Algebra - formula
    Does anyone know the formula or how to format the following word problem?

    Painter X can paint a house in 4 hours. Painter Y can paint the same house in 6 hours. How long will it take for both painters to paint the same house together?

    I was told the answer was 2 hours and 24 minutes but don't know how to put it in a formula that can be worked.

    Thanks for the assistance.

    Dave
  • Nov 2, 2008, 02:34 PM
    galactus


    Solve for t and convert from decimal to hours and minutes.

    You can also do this:



    Gives same answer.

    For the second method, we are figuring up the time to paint 1/4th the house and 1/6th the house. Together, 1 whole house is painted.
  • Nov 4, 2008, 02:04 AM
    Unknown008

    Yup, one painter alone would take more time than when both painters work together.
  • Nov 9, 2008, 10:04 PM
    Jleon

    I hahve almost the same as galactus, but equal to 1/T ,i.e
    1/4 + 1/6=1/T
    5/12=1/T you switch both fractions and you have T=12/5 equal to 2 2/5 (2/5 of 60 minutes is equal 24 minutes)
    Final answer: 2 hrs and 24 minutes

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