A helicopter traveling at 2225km/hr left San Jose 1h after a train that had departed at 7:00am. If the helicopter overtook the train in .8h find the avg speed of the train.
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A helicopter traveling at 2225km/hr left San Jose 1h after a train that had departed at 7:00am. If the helicopter overtook the train in .8h find the avg speed of the train.
Did you try to make a sketch? Or better, a distance - time graph?
In any case, did you understand that for the helicopter to overtake the train, it must have covered a certain distance, equal to what the train did in 0.8 hours?
From this, find the distance covered by the helicopter. This is the same distance covered by the train in 1.8 hours (since it left 1 hour before the helicopter). With this, you should be able to find the speed of the train!
Hope it helped!
I want to know where you got a helicopter that can travel at twice the speed of sound ;) (What I'm trying to say is the speed of the train is not going to be anything sensible, so don't expect it to be!)
Yup, quite strange, lol!! :p
A baseball batter hits the ball ang reaches the third base of the diamond whose bases are 24meter apart in 15 second.what is his average speed?
A baseball batter hits the ball and reaches the third base of the diamond whose bases are 24meter apart in 15 second .what is his average speed?
... mam faster,,
A baseball batter hits the ball ang reaches the third base of the diamond whose bases are 24meter apart in 15 second.what is his average speed?
A baseball batter hits the ball ang reaches the third base of the diamond whose bases are 24meter apart in 15 second.what is his average speed?
Artjanbel - you should no tag a new question onto an olod one, but should instead start a new thread.
From the above discussion you should know that average speed = distance traveled divided by time. You are given the time, so the only "trick" is to know the distance traveled. In this problem you need to know that in American baseball after hittting the ball the batter runs from "home plate" to "first base" then "2nd base" then "3rd base." So in 15 seconds he travels 3 legs of the base paths, each leg being 24m in length. Can you take it from here?
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