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-   -   Quadratic Equation (https://www.askmehelpdesk.com/showthread.php?t=266832)

  • Oct 6, 2008, 03:30 PM
    karebear11
    Quadratic Equation
    A rectangular lawn measures 7m by 5m. A uniform border of flowers is to be planted along two adjacent sides of the lawn. If the flowers that have been purchased will cover an area of 6.25 m^2, how wide is the border?
  • Oct 6, 2008, 04:36 PM
    EuRa
    There might be more than 1 way to solve this, but here's what I come up with:

    The lawn with flowers looks something like this:



    Code:

                  7
    ------------------------------------
    | X  |          FLOWERS            |
    |----|------------------------------|
    |    |                              |
    |    |                              |  5
    |  F |          LAWN                |
    |    |                              |
    |    |                              |
    ------------------------------------


    So the area of the top row = 7 * X

    The area of the side row = 5 * X

    However, they overlap, and the part that overlaps = X * X , and it has to be subtracted from your total because otherwise it will be counted twice.

    So your original equation is: (7X) + (5X) - (X^2) = 6.25


    Combine: 12X - X^2 = 6.25

    Then subtract from 1 side and put everything on the other. I like making the X^2 positive, so I add that to both sides and subtract 12X from both sides. That gives me:

    0 = X^2 - 12X + 6.25

    Then graph and solve.

    I got 11.45 and 0.546. Only one of those is the answer.

    If you plug those numbers back in, 11.45 doesn't work because 7 * 11.45 plus 5 * 11.45 = too big.

    But 0.546 works.

    0.546 * 7 + 0.546 * 5 = 6.552

    Then subtract .55 * .55 = 6.25-ish

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