Two numbers have a difference of 3. the sum of their squares is 89.
Find the numbers.
Having difficulty please help

Quote:

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Originally Posted by yoohoo

two numbers have a difference of 3. the sum of their squares is 89.
find the numbers.
Having difficulty please help

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Call one number a
The other number is a+3
As per data a^2 + (a+3)^2 = 89

a^2 + (a^2 + 6a + 9) = 89
a^2 + a^2 + 6a +9 = 89
2a^2 + 6a = 80
a^2 + 3a = 40
a^2 +3a - 40 = 0

Just solve a from that, and you have both numbers.

(you have to do something yourself... just see how the number 40 is build up... start dividing with two... Find two numbers that multiply to -40, but add up to +3)

Easy, is it not ?

:)