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Pendulum solving

How the pendulum works on moon ?

The period for the swing of a pendulum of length $L$ is given by (approximately):

$<br /> T (sec)= 2 \pi sqrt {L/g}<br />$

The term $g$ is the acceleration due to gravity. From this can you tell what happens to the period $T$ if $g$ is made smaller, as on the surface of the moon?

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