Ask Me Help Desk

Ask Me Help Desk (https://www.askmehelpdesk.com/forum.php)
-   Math & Sciences (https://www.askmehelpdesk.com/forumdisplay.php?f=402)
-   -   Factoring equation (https://www.askmehelpdesk.com/showthread.php?t=248826)

  • Aug 14, 2008, 08:49 AM
    murcorm
    Factoring equation
    Factor completely: 5x 3 + 8x 2 – 5x + 8
  • Aug 14, 2008, 09:50 AM
    galactus
    Are you sure that isn't ?

    As it is with that +8 at the end it is not nicely factorable.

    But with a -8, it is. Let me know before I proceed.
  • Aug 14, 2008, 10:31 AM
    Rehaan_genius
    if the equation is as galactus had written, then proceed as follows;
    5x^3+8x^2-5x-8
    now see carefully-
    (5x^3+8x^2)-(5x+8)
    x^2(5x+8)-1(5x+8)
    (x^2-1)(5x+8)
    so;(if the equation is equal to zero)
    x= +1,-1,-8/5
    Dude, got it or not?
  • Aug 14, 2008, 02:28 PM
    galactus
    Remember, you can factor it further because of the

  • Aug 15, 2008, 02:35 AM
    Rehaan_genius
    Yes! By using the formula-> a^2-b^2=(a-b)(a+b)

  • All times are GMT -7. The time now is 03:09 PM.