Find the domain of f(x)= 1/7x - the square root of (5-x)

I thought it was x > 5 but I was wrong.

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Originally Posted by blizydee

Find the domain of f(x)= 1/7x - the square root of (5-x)

I thought it was x > 5 but I was wrong.

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At first glance, I would say that x <> 0.

If you don't want complex numbers in the solution set, x <= 5, too.

From -infinite to 5 unless 0