1) Solver for x:

log7(x+4) + log7(x-2)=1

First, recall the rule: Log(a*b) = log(a) + log(b). So the first step in your problem is to combine the two log terms - here I assume that when you wrote log7(x+4) you meant:

, correct?

So:


Now raise both sides by the power of 7 (the base of the log), recalling that


Can you take it from here?

Quote:

---

Originally Posted by gsingh7

1) Solver for x:

log7(x+4) + log7(x-2)=1

---

7x+4+7x-14=1
14x=1+14-4
14x=11
x=1.3