Ask Me Help Desk

Ask Me Help Desk (https://www.askmehelpdesk.com/forum.php)
-   Math & Sciences (https://www.askmehelpdesk.com/forumdisplay.php?f=402)
-   -   Grade 11 Physics: Velocity at Half-time (https://www.askmehelpdesk.com/showthread.php?t=235344)

  • Jul 8, 2008, 06:41 PM
    summerschool
    Grade 11 Physics: Velocity at Half-time
    It is true that "during constant acceleration, the average velocity for an interval is equal to the instantaneous velocity at half-time in the interval."

    What I don't understand is, what is half-time and how do we obtain it?

    Also, What does the area under a velocity-time graph give for a moving object? My guess is acceleration... is this right?

    Thanks so much! :)
  • Jul 9, 2008, 04:54 AM
    Unknown008
    Constant acceleration is a straight line with a positive gradient on a velocity-time graph. If you make the 'average' velocity, you'll obtain the midpoint, i.e. where the time between the intervals is half (thus half-time). Half time can be calculated using the formula for average. Since you are using a time interval, you'll have only two time instants. Average (or half time) is:
    (initial time+final time)/2

    Quote:

    Also, What does the area under a velocity-time graph give for a moving object? My guess is acceleration... is this right?
    Unfortunately, no. The answer is distance. You have the acceleration by the gradient of the graph.

    Hope that helped!

  • All times are GMT -7. The time now is 12:55 AM.