(R+ωL)(R-ωL)
= R^2-ωL
Z^2-R^2
= (Z+R)(Z-R)
h= -4.9t^2+55t+12
make ‘t’ subject
h= -4.9t^2+55t+12
h-12=-4.9t^2+55t+12
-12h=50.1t
-12h/50.1=t
Thank you
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(R+ωL)(R-ωL)
= R^2-ωL
Z^2-R^2
= (Z+R)(Z-R)
h= -4.9t^2+55t+12
make ‘t’ subject
h= -4.9t^2+55t+12
h-12=-4.9t^2+55t+12
-12h=50.1t
-12h/50.1=t
Thank you
For the last one, you can't subtract a t term from a t^2 term:confused: .
You just broke the laws of algebra. :) :rolleyes: :p
You can easily check your answer by subbing it back in to the equation. If it works, you should get h. But you won't.:eek:
Try completing the square. Can you do that?
Upon doing that you get
Multiply the right side by 5 to get the denominators the same, then we get:
There, see what happened?
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