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-   -   Physics/trignometry 140N and 35 deg (https://www.askmehelpdesk.com/showthread.php?t=214035)

  • May 8, 2008, 07:00 PM
    long3
    physics/trignometry 140N and 35 deg
    So it says that a vector 140N is oriented at 35 deg with the horizontal. What is the magnitude of the horizontal component?
    So I figured this is somewhat of a trig question with the vector being 140N and the theta or angle between this triangle being 35 degrees.
  • May 9, 2008, 04:43 AM
    galactus
    The horizontal component would be 140cos(35)

    The vertical 140sin(35)
  • May 9, 2008, 06:58 AM
    iamthetman
    I agree with the horizontal component.

    The vertical component would be 140sin(35).
  • May 9, 2008, 10:30 AM
    galactus
    DUH, that's what I meant. Mistyped. Thanks for the catch
  • May 9, 2008, 11:03 AM
    iamthetman
    I thought so.

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