Team A has probability 2/3 of winning whenever it plays. If A plays 6 games, find the probability that A wins, 1. two games, 2. at least one game, 3. more than half of its games.

The is binomial in nature.

p=2/3, q=1/3

part 1:

part 2, same as above only with 2 instead of 1.

part 3: The best thing for at least 1 is find the probability of 0 and subtract from 1:



part 4: More than half means 4, 5, or 6 games.



I will leave you do the number crunching. Okey-doke?