-4(y+2) = (x-3)^2
I need help finding the vertex, axis, p, focus, and directrix. I'm so blanked out.I cannot remember anything.
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-4(y+2) = (x-3)^2
I need help finding the vertex, axis, p, focus, and directrix. I'm so blanked out.I cannot remember anything.
This is a parabola with equation
It has the form
Where h and k are the coordinates of the vertex.
It has vertex at (3,-2) and is concave down.
You were wondering what 'p' represented. That is the distance from the focus to the vertex.
To find the focus and directrix of this parabola:
It has the form.
In this case, where
Thus, the parabola opens downward and has focus
The directrix is the horizontal line, which is a distance 1 from the vertex.
I made a mistake on the graph. The directrix should read y = -1.
identify the vertex, focus and the directrix of y=1/24x^2
identify the vertex, focus and the directrix of y=1/24x^2
Please start your own thread. Piggy backing on an old thread is not a good idea.
Notice that it has the form.
Since 1/24 is positive, the parabola is concave up and has vertex at the origin.
.
Solve for p. p is the distance from the vertex to the focus and from the vertex to the directrix.
The directrix has equation y=-p and the focus has coordinates (0,p)
x^2 = -36y what is the directrix?
solving for directrix?
1st, you must find the axis in equation x^2 = 4ay, then divide -36 by -4 by the process of canceling.. The answer is 9.. therefore a=9 (the axis is 9)..
2nd you must find the focus.. then you can now solve for the directrix..
This is a parabola with vertex at the origin and concave down.
As Mr. Woman pointed out, p=9.
Thus, the directrix is 9 units from the vertex.
To see it, graphon a calculator or some other software.
If you do not have a calculator, go here and download the free graphing utility.
Graph
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