So if you have an alpha particle accelerated to 23.1 MeV per particle. How do you convert it to find the energy in kJ/mole?

Well, you know how many J are in an eV (same as the electronic charge), and you know how many particles in a mole (Avagadro's constant), so I fail to see where you are having difficulty.

Do you have to do anything with the alpha particle?
Do you set it up like this?
23.1×10^6(1.602×10^-13)(6.02×10^23)/10^3

Quote:

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Originally Posted by chemdiaster

Do you have to do anything with the alpha particle?
Do you set it up like this?
23.1×10^6(1.602×10^-13)(6.02×10^23)/10^3

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Nope, nothing special, but some of your powers here are a bit confused.

1.602×10^-13 is the number of Joules in an MeV, so take that into account.

so should it be 1.602×10^-19?
With an answer of 2.23×10^3 kJ/mole

Are you sure? Just looking at the powers it looks to be around 10^7

this is how I set it up~
23.1MeV/ particle=
(23.1×10^6 eV/particle)(1.602×10^-19 J/ 1eV)(kJ/1×10^3 J)( 6.02×10^23 particles/1 mole)

I get 2.23x10^9 kJ/mol from that calculation.

After recalcutlating it I got that answer. Do you know anything about radioactive and stable nuclides?