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  • Mar 14, 2008, 06:08 AM
    sawsan
    abstract algebra
    show that the set R of all multiples of 3 is a subring of Z .
  • Mar 14, 2008, 10:42 AM
    galactus
    Here's a start. There must be closure under additon and multiplication.

    The set 3Z of all multiples of 3 is a subring.

    Take ; let a=3x and b=3y.

    Then

    and

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