Ask Me Help Desk

Ask Me Help Desk (https://www.askmehelpdesk.com/forum.php)
-   Other Engineering (https://www.askmehelpdesk.com/forumdisplay.php?f=561)
-   -   Heat Energy Requirement (https://www.askmehelpdesk.com/showthread.php?t=191781)

  • Mar 6, 2008, 01:29 PM
    mrm574
    Heat Energy Requirement
    I am trying to calculate the heat energy required to raise the temperature of a solution containing 34,624kg of silica, 7,252kg of water and 224kg of sulphuric acid from 298K to 423K (i.e delta T = 125K). This seems a simple problem; I have the respective specific heat capacities of silica, water and sulphuric acid as 745, 4.18 and 1.42 kJ/kgK.

    I've used the equation Q = ΔT.Σmicp,I where I stands for species I.

    I get the answer to be 3,228,205,500kJ which seems stupidly big!

    Help! It's for an engineering design project with the deadline drawing ever closer!
  • Mar 11, 2008, 03:34 PM
    caibuadday
    Quote:

    Originally Posted by mrm574
    I am trying to calculate the heat energy required to raise the temperature of a solution containing 34,624kg of silica, 7,252kg of water and 224kg of sulphuric acid from 298K to 423K (i.e delta T = 125K). This seems a simple problem; I have the respective specific heat capacities of silica, water and sulphuric acid as 745, 4.18 and 1.42 kJ/kgK.

    I've used the equation Q = ΔT.Σmicp,i where i stands for species i.

    I get the answer to be 3,228,205,500kJ which seems stupidly big!

    Help! It's for an engineering design project with the deadline drawing ever closer!

    don't you have to converse T into C value ?
  • Mar 13, 2008, 05:21 AM
    mrm574
    No because it's a temp. difference, so they're the same.
  • Mar 15, 2008, 02:37 PM
    caibuadday
    Quote:

    Originally Posted by mrm574
    I am trying to calculate the heat energy required to raise the temperature of a solution containing 34,624kg of silica, 7,252kg of water and 224kg of sulphuric acid from 298K to 423K (i.e delta T = 125K). This seems a simple problem; I have the respective specific heat capacities of silica, water and sulphuric acid as 745, 4.18 and 1.42 kJ/kgK.

    I've used the equation Q = ΔT.Σmicp,i where i stands for species i.

    I get the answer to be 3,228,205,500kJ which seems stupidly big!

    Help! It's for an engineering design project with the deadline drawing ever closer!

    yes Q= mc Dt, you need more information; the water you have is 125C, above 100C (steam) the c value is defferent... do you know at what temps. Silica or sulp. Acid change phase?. yes this is a very simple problem

  • All times are GMT -7. The time now is 12:25 PM.