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-   -   Solving trionometric identities. (https://www.askmehelpdesk.com/showthread.php?t=188645)

  • Feb 26, 2008, 05:25 PM
    americalvr
    solving trionometric identities.
    somebody pleease help me. :confused: I've tried figuring out this problem and can't seem to get it. :mad: you have to verify the trig identity

    the problem is
    (cotx/cosx)+(secx/cotx)=sec2xcscx


    pleeease help me.
  • Feb 26, 2008, 05:36 PM
    rockerchick_682
    Uh it's been a while. But have you tried converting them all to cosx and sinx? Isn't cotx cosx over sinx? And secx is 1/cosx? Well I'd try that. Keep trying to substitute all the rules in
  • Feb 27, 2008, 07:51 AM
    galactus
    You have some bad notation. You have when you mean . Please use the ^ for powers. Better yet, if you plan on posting to any extent, try learning a little LaTex. If you wish, you can click on 'quote' at the bottom of my post to see the code I used to display it.



    The previous advise was good. Convert the left side to sin and cos.





    Now, can you continue? A little cross multiplying and you should see it fall together.. Write back if you remain stuck. Just remember your identities. may prove handy.

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