I have f'(x) = x(2ln(x) - 3) / (ln(x) - 1)^2 (which matches my book's answer)
My book says setting this equal to zero gives:
2ln(x) - 3 = 0
I think this implies that x / (ln(x) - 1)^2 equals 1
or (ln(x) - 1)^2 = x
but I don't understand why!
I need to see the steps.
Thanks,