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-   -   How do I solve this? (https://www.askmehelpdesk.com/showthread.php?t=179571)

  • Feb 2, 2008, 07:36 AM
    koevenig
    How do I solve this?
    3(x+4) <or= 3x
  • Feb 2, 2008, 07:56 AM
    Capuchin


    expanding brackets:



    This is obviously never true.
  • Feb 2, 2008, 08:02 AM
    PolluxCastor
    You are trying to find a range for which the statement is true.

    Simplify as if it were a normal equality. If at some point you multiply or divide by a negative number (in this case I don't think that is likely), remember to reverse the inequality.

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