5 (to the power x + 3 ) minus (5 to the power x+1) =600
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5 (to the power x + 3 ) minus (5 to the power x+1) =600
Two barrels A and B contain unspecified amounts of cider, with A containing more than B.From A, pour into B as much cider as B already contains. Then from B, pour into A as much cider as A now contains. Finally, pour from A into B as much cider as B now contains. Each barrel now contains 64 liters of cider. How many liters of cider were in each barrel at the start of the process.
Please start your own thread.
May I ask why you dug up an old thread almost a year and a half old instead of starting a new one?
its too simple
just split the 5^x+3 as 5^x * 5^3
do the same thing for the other term
take out 5^x common
simplify
u will get x as 1
I don't think it much matters anymore. That post was from over a year ago. The post I was speaking of is this one:Quote:
Originally Posted by ashwanth
Why the poster dug up this old post and 'piggy-backed' on it, is beyond me. I asked them to start their own thread. It is more apt to get noticed that way. They never responded, so I assume it doesn't really matter to them, after all.Quote:
Two barrels A and B contain unspecified amounts of cider, with A containing more than B.From A, pour into B as much cider as B already contains. Then from B, pour into A as much cider as A now contains. Finally, pour from A into B as much cider as B now contains. Each barrel now contains 64 liters of cider. How many liters of cider were in each barrel at the start of the process.
But, to solve this problem is to pick it apart.
The first part says to pour the same amount that is in B from A into B:
The two amounts are then:
This leads to two equations to solve:Code:A-B 2B
Continuing:
2(A-B) 2B-(A-B)
2(A-B)-(2B-(A-B)) 2(2B-(A-B))
-2A+6B=64
3A-5B=64
Solving, we find A=88 and B=40 are the amounts initially in the barrels.
(6 x 2) + 7 - 3 + 5
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