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  • Jan 23, 2008, 04:47 PM
    nick1993
    Math area, dimensions
    If I knew that the area of my yard is 30 sq ft and I had 34 ft of fencing, how would I solve this problem? I can't figure this one out. Please help!
  • Jan 23, 2008, 05:02 PM
    littlebear91
    2(l+w)=34 ft of fencing, where l= length and w= width of this rectangle
    l*w=30

    2l+2w=34
    2l=34-2w
    l=17-w

    sub l into l*w=30
    (17-w)*w=30
    -(w square) + 17w=30
    using completing the square
    -(w squared -17w + ((17)square/(2) square)-(17square /2 square)=30
    -(w- (17/2)square)square + 72.25=30
    -(w- (17/2)square)square=-42.25
    turns both side positive
    (w- 72.25)square=42.25
    squareroot

    w-72.25=+- sqrt 42.25
    w1=+6.5+72.25 w1=78.75
    w2=-6.5+72.25 w2=65.75

    edit* hopes this help, if don't get it, go on Google and search as to how to solve quadratic equations.

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