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-   -   Mathmatical sequence is impossible (https://www.askmehelpdesk.com/showthread.php?t=173332)

  • Jan 16, 2008, 10:56 PM
    jeremyphilip
    4, 16, 37, 58, 89, 145, 42, 20

    You may use any type of sequence to answer this question. Help:confused:

    Its impossible to answer such a question
  • Jan 17, 2008, 02:20 AM
    Capuchin
    You take the sum of the squares of the digits of the previous term. It's not impossible at all.

    In fact you have the whole sequence there, it just repeats from the beginning from that point. (the next terms are 4, 16, 37 etc.)

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