How can I develop a classless addressing scheme for network 192.168.1.0/24 for Lab 1 with 60 hots, Lab 2 with 12 hosts and Lab 3 with 40 hots.

What will be the appropriate classfull addressing scheme for these LAN segments :confused:

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Originally Posted by shalom4U

How can I develop a classless addressing scheme for network 192.168.1.0/24 for Lab 1 with 60 hots, Lab 2 with 12 hosts and Lab 3 with 40 hots.

What will be the appropriate classfull addressing scheme for these LAN segments :confused:

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Since a 24 bit Classless network is equivalent to a Class C network, you can use the following as an example:

Lab 1
Network ID 192.168.1.0/24
Subnet Mask 255.255.255.0
Gateway 192.168.1.1
DHCP Scope 192.168.1.100 to 195

Lab 2
Network ID 192.168.2.0/24
Subnet Mask 255.255.255.0
Gateway 192.168.2.1
DHCP Scope 192.168.2.100 to 125

Lab 3
Network ID 192.168.3.0/24
Subnet Mask 255.255.255.0
Gateway 192.168.3.1
DHCP Scope 192.168.3.100 to 163

To use the 192.168.1.0 address your subnet mask will be 255.255.255.192 with /26 (CIDR); this yields 62 hosts per subnet and 4 subnets.

Lab 1
Subnet is 192.168.1.0
Mask is 255.255.255.192
Host Range is 192.168.1.1 to 192.168.1.62
Broadcast is 192.168.1.63

Lab 2
Subnet is 192.168.1.64
Mask is 255.255.255.192
Host Range is 192.168.1.65 to 192.168.1.126
Broadcast is 192.168.1.127

Lab 3
Subnet is 192.168.1.128
Mask is 255.255.255.192
Host Range is 192.168.1.129 to 192.168.1.190
Broadcast is 192.168.1.191

Classless (Network 192.168.1.0/24 is variably subnetted):
Lab 1
Subnet ID with mask is 192.168.1.0/26
(i.e. Mask is 255.255.255.192)
Host Range is 192.168.1.1 to 192.168.1.62 (i.e. 62 addresses)
Broadcast is 192.168.1.63

Lab 2
Subnet ID with mask is 192.168.1.64/28
(i.e. Mask is 255.255.255.240)
Host Range is 192.168.1.65 to 192.168.1.78 (i.e. 14 addresses - enough for 12 addresses)
Broadcast is 192.168.1.79

Lab 3
Subnet is 192.168.1.80/26
(i.e. Mask is 255.255.255.192)
Host Range is 192.168.1.81 to 192.168.1.142 (i.e. 62 addresses - enough for 40 addresses)
Broadcast is 192.168.1.143

as an example the remaining (256-144) 112 addresses could be subnetted(e.g. 1 x 16, 1 x 32 and 1 x 64)
Subnet IDs:
192.168.1.144/28
192.168.1.160/27
192.168.1.192/26 making a total of 7 subnets


Classful (The Class C Network 192.168.1.0 is subnetted 'stealing host bits' for 4 subnets with 64 addresses each):

Lab 1
Subnet ID with mask is 192.168.1.0/26
(i.e. Mask is 255.255.255.192)
Host Range is 192.168.1.1 to 192.168.1.62 (i.e. 62 addresses enough for 60 addresses)
Broadcast is 192.168.1.63

Lab 2
Subnet ID with mask is 192.168.1.64/26
(i.e. Mask is 255.255.255.192)
Host Range is 192.168.1.65 to 192.168.1.126 (i.e. 62 addresses - enough for 12 addresses)
Broadcast is 192.168.1.127

Lab 3
Subnet is 192.168.1.128/26
(i.e. Mask is 255.255.255.192)
Host Range is 192.168.1.129 to 192.168.1.190 (i.e. 62 addresses - enough for 40 addresses)
Broadcast is 192.168.1.191

possibilities of using only one more subnet for the remaining 64 addresses as the subnetting size is fixed
by the requirement of classful network and largest network with 60 hosts

Where I said 7 subnets I meant 6 subnets