Ask Me Help Desk - Proving A Trigonometric Identity

Usually I am pretty good at these, but this one is killing me. Please help!

Never mind I solved it. Here's the answer if anyone is curious.

$\frac{sin^2\theta-tan\theta}{cos^2\theta-cot\theta}=tan^2\theta$

$\frac{sin^2\theta-\frac{sin\theta}{cos\theta}}{cos^2\theta-\frac{cos\theta}{sin\theta}}$

$\frac{\frac{sin^2\theta cos\theta-sin\theta}{cos\theta}}{\frac{cos^2\theta sin\theta-cos\theta}{sin\theta}}$

$\frac{\frac{sin\theta(sin\theta cos\theta-1)}{cos\theta}}{\frac{cos\theta(sin\theta cos\theta-1)}{sin\theta}}$

$(\frac{sin\theta(sin\theta cos\theta-1)}{cos\theta}) X (\frac{sin\theta}{cos\theta(sin\theta cos\theta-1)})$

$\frac{(sin\theta)(sin\theta)(sin\theta cos\theta-1)}{(cos\theta)(cos\theta)(sin\theta cos\theta-1)}$

$\frac{(sin\theta)(sin\theta)\cancel{(sin\the ta cos\theta-1)}}{(cos\theta)(cos\theta)\cancel{(sin\theta cos\theta-1)}}$

$\frac{sin^2\theta}{cos^2\theta}$

$\frac{sin^2\theta}{cos^2\theta}=tan^2\theta$