4x/(x-3) - 2x / (x-2)
![]() |
4x/(x-3) - 2x / (x-2)
Do you have a question or are we supposed to guess?
Whatever your question, show your work and we'll help you out.
Use the following method:
a/b + c/d = (ad + bc)/bd
4x/x-3 - 2x/x-2
4x(x-2) - 2x(x-3)/x-3*x-2
4x^2-8x-2x^2+6x/x-3*x-2
2x^2-2x/x-3*x-2
2(x^2-1)/x^2 - 5x - 6
this must b the answer
wouldn't the answer be 2x^2 - 14x:confused:
I wiil try to solve it once again... but I think that must be the answer... I willl try once again
No... the answer u are telling is not correct... so try it again
4x/(x-3) - 2x / (x-2)
= [4x (x -2 ) -2x (x -3)]/(x-3)(x-2)
= (4x^2 - 8x - 2x^2 + 6x)/(x-3)(x-2)
= (2x^2 -2x)/(x-3)(x-2)
= 2x (x -1)/(x -3) (x -2)
2^x+4x-1
4x/x-3-2x/x-3=4x(x-2)-2x(x-3)=4x^2-8x-2x^2+6x=2x^2-2x=1Quote:
Originally Posted by mgots
All times are GMT -7. The time now is 07:01 PM. |