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-   -   Algebra (https://www.askmehelpdesk.com/showthread.php?t=162052)

  • Dec 12, 2007, 01:28 PM
    mgots
    algebra
    4x/(x-3) - 2x / (x-2)
  • Dec 12, 2007, 01:38 PM
    asterisk_man
    Do you have a question or are we supposed to guess?
    Whatever your question, show your work and we'll help you out.
  • Dec 12, 2007, 04:47 PM
    jiten55
    Use the following method:

    a/b + c/d = (ad + bc)/bd
  • Dec 13, 2007, 03:16 AM
    itsme_vipsdude
    4x/x-3 - 2x/x-2
    4x(x-2) - 2x(x-3)/x-3*x-2
    4x^2-8x-2x^2+6x/x-3*x-2
    2x^2-2x/x-3*x-2
    2(x^2-1)/x^2 - 5x - 6
    this must b the answer
  • Dec 21, 2007, 07:46 AM
    Shy But Nice
    wouldn't the answer be 2x^2 - 14x:confused:
  • Dec 21, 2007, 08:44 AM
    itsme_vipsdude
    I wiil try to solve it once again... but I think that must be the answer... I willl try once again
  • Dec 21, 2007, 08:50 AM
    itsme_vipsdude
    No... the answer u are telling is not correct... so try it again
  • Dec 21, 2007, 04:53 PM
    jiten55
    4x/(x-3) - 2x / (x-2)

    = [4x (x -2 ) -2x (x -3)]/(x-3)(x-2)

    = (4x^2 - 8x - 2x^2 + 6x)/(x-3)(x-2)

    = (2x^2 -2x)/(x-3)(x-2)

    = 2x (x -1)/(x -3) (x -2)
  • Jan 3, 2008, 01:49 AM
    mustapha
    2^x+4x-1
  • Jan 3, 2008, 02:02 AM
    mustapha
    Quote:

    Originally Posted by mgots
    4x/(x-3) - 2x / (x-2)

    4x/x-3-2x/x-3=4x(x-2)-2x(x-3)=4x^2-8x-2x^2+6x=2x^2-2x=1

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