The kelvin temperature of one liter of gas is doubled and its pressure is tripled, what's the volume?

This is a straight-forward application of the Ideal Gas Law: PV=nRT, where P=pressure, V=volume, n= amount of gas in terms of number of moles, R = constant, and T= temp in Kelvins. Since you are interested in volume, rewrite this as: V = nRT/P. Now, if you double T and triple P, can you now see how V changes? Post back with your final answer.