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-   -   Solve for z 3x(y+1)=9+z where y=4, x=2 (https://www.askmehelpdesk.com/showthread.php?t=152735)

  • Nov 16, 2007, 08:54 AM
    resa35
    Solve for z 3x(y+1)=9+z where y=4, x=2
    Solve for z 3x(y+1)=9+z where y=4, x=2

    Can you help me solve step by step
  • Nov 16, 2007, 09:59 AM
    asterisk_man
    substitute y=4 and x=2, simplify and solve. Why don't you show us your work and let us know where you're having problems.
  • Nov 18, 2007, 12:04 PM
    plynia
    Quote:
    Originally Posted by resa35
    Solve for z 3x(y+1)=9+z where y=4, x=2

    Can you help me solve step by step
    OK
    3x(y+1)=9+z
    3(2)(4+1)=9+z
    6(4+1)=9+z
    6(5)=9+z
    30=9+z
    30-9=9+z-9
    21=z

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