A 300g piece of aluminum is heated from 30 degrees C to 150 degrees C. What amount of heat energy is absorbed?
The specific heat capacity of aluminum is: 900

I tried doing this question.. and substituting it in the formula Q=m c DeltaT

but I get a different answer from my teacher's answer.

Can someone help and tell me what I'm doing wrong, or if I am missing a step?

H=mst
H=0.3kg x 900 x 120
H= 32400 joules

Just remember to convert your given mass to kg, and apply the formula