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  • Nov 7, 2007, 05:59 PM
    talaskinboit
    pre cal
    what is the inverse cotangent of negative square root of three divided by three?

    theta = cot(inverse) (negative Squareroot 3)/3
  • Nov 7, 2007, 06:15 PM
    s_cianci
    It's whatever angle, in radians, has a cotangent value of -sqrt(3)/3.

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