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-   -   How to solve these equations (https://www.askmehelpdesk.com/showthread.php?t=147600)

  • Nov 1, 2007, 08:07 PM
    maiemaie
    how to solve these equations
    * -5x+4=29



    * 6(2a-3) =-30



    * lx+3l =4

    * is it a paralle, perpendicular, or neither?
    Line1: through (2,10) and (1,5)
    Line2: through (3,-7) and (8,-8)


    * x<-3


    * y<-x+4
  • Nov 1, 2007, 08:18 PM
    shorty777
    x=5

    a=-4

    x=1

    paralle

    x=-4

    y=10 x= -3

    I don't know for sure I'm just gesing if it helps at all
  • Nov 1, 2007, 08:20 PM
    Gernald
    the first two you need to get x on one side and that'll be your answer.
    #3 I think has 2 answers because 3 can be put to the otherside as -3 or +3
    #4 you can graph using a normal x y coordinate plane and that'll give you the answer.
    What are you looking for on the last two? X?

    Good Luck
  • Nov 1, 2007, 08:22 PM
    rankrank55
    For the equations, solve for the unknown. In order to tell whether the two lines are parallel, perpendicular, or neither you must plot them on a graph and see what type of line relationship they have.

    I will help you with the first *... -5x+4=29... remember... you must use order of operations
    -5x+4=29

    -5x=29-4
    _______
    -5x=25 (now you must get the x by itself)
    _______
    x=25/-5 (dividing 25 by -5)
    _______
    x=-5

    Hope this helps you understand these a little bit more!
  • Nov 1, 2007, 08:26 PM
    rankrank55
    Quote:

    Originally Posted by shorty777
    x=5

    a=-4

    x=1

    paralle

    x=-4

    y=10 x= -3

    i don't know for sure i'm just gesing if it helps at all

    That was meant to be a disagree... some of these are INCORRECT!!
  • Nov 1, 2007, 08:44 PM
    shorty777
    That is why I said that I don't know for sure
  • Nov 1, 2007, 08:47 PM
    rankrank55
    Yes, but it's best to not post if you do not know for sure... especially with problems that have a definite right and wrong answer...
  • Nov 1, 2007, 08:49 PM
    shorty777
    Okay what ever
  • Nov 1, 2007, 08:50 PM
    rankrank55
    Glad you got it!! :D

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