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  • Oct 24, 2007, 06:22 AM
    sarabear414
    College Algebra
    If f(x)= 3x^2 +7 Then how do you solve f(2x+3)?
  • Oct 24, 2007, 06:26 AM
    ebaines
    Simply plug "2x+3" in place of the "x" in f(x) = 3x^2+7. You get: f(2x+3) = 3(2x+3)^2+7. You can take it from there and simplify.

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