How do you do these 2 types of problems
1.) sin (t)= -sqrt 3/2

sin (t)= sqrt 2/2

2.) (cos (t))^2= 1/2

Answers have to be in radians.. please help :(

You should carefully read your text book and focus on the definitions of sin and cosine, as well as the definition of radians. I'll give you a hint on the second problem here. If [cos(t)]^2 = 1/2, then cos(t) = sqrt (1/2). From the definition of he cosine, that means that the ratio of the adjacent side to the hypotenuse is 1/sqrt(2). So what would the length of the opposite side of the triangle be? Use Pythagorean's theorem to find that, and then ask yourself, what must the angle be to have a triangle with these lengths of sides?