A diver jumps vertically with a velocity of 4.0m/s from a platform and enters the water 1. seconds later. If she falls with an acceleration due to gravity of 9.8 m/s^2, what is her final velocity?

Vf= Final Velocity ?
Vo= Original Velocity 4 m/s
a= Acceleration 9,8 m/s^2
t= Time 1 s

Vf=Vo+a(t) 13,8 m/s

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Originally Posted by DoctorK

Vf= Final Velocity ?
Vo= Original Velocity 4 m/s
a= Acceleration 9,8 m/s^2
t= Time 1 s

Vf=Vo+a(t) 13,8 m/s

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I believe the question requires v0 to be set as -4m/s, not +4m/s.

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Originally Posted by Capuchin

I believe the question requires v0 to be set as -4m/s, not +4m/s.

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As the question states "A diver jumps vertically" I assumed the diver jumped DOWN in which case the original value is correct, and V0= +4.

If the diver jumps UPWARDS, then your appreciation is correct, and V0= -4.

DoctorK, please demonstrate how to jump down. I'd love to see it. :)

Quote:

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Originally Posted by asterisk_man

DoctorK, please demonstrate how to jump down. I'd love to see it. :)

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Had to spread the rep, but this is exactly the point I was trying to make (albeit subtly). Plugging numbers into an equation is fine and dandy, but not at the cost of common sense. :)