A 1000kg safe is 2.0m above a heavy-duty spring when the rope holding the spring breaks. The safe hits the spring and compresses it 50 cm. What is the spring constant of the spring?

GPE = KE
mgh = (1/2) mv^2
gh = (1/2) v^2
(9.8)(2) = (1/2) v^2
39.2 = v^2
6.26 m/s

KE = EPE

(1/2)(1000) (6.26) = (1/2) k (.5^2)
24040N/m = k

Is this correct??