Can someone help me with this problem?
A solution of calcium hydroxide required 26.42 ml to neutralize .914 g of potassium hydrogen phthalate. What was the molarity of the calcium hydroxide solution? This equation is given:
Ca(OH)2 + 2KHC8H4O4= CaC8H4O4+ K2C8H4O4 + 2H2O
The molarity of the potassium hydrogen phthalate is .914 g/.02642 L. or 34.60 g / L. I can get that. I'm confused as how to determine the molarity of the calcium hydroxide.