domain question> http://i207.photobucket.com/albums/b...EvErSe_/16.jpg
triangle question> http://i207.photobucket.com/albums/b..._/untitled.jpg
NOTE : PLEASE IGNORE THE NUMBER 1 MARKED ON TOP OF THE RECTANGLE IN THE TRIANGLE QUESTION (I DREW THAT).
I have the domain one but I'm not sure if I did it right, I got domain is (negative infinity, positive infinity) and my graph is going up with a top and then curves down like an upside down u and then for the secod question part a I got P(x,1/2) and part b I can't figure out the lengths of the rectangle ? If anyone could help it would be much appreciated thank you in advance. I'm just really worried ><

It looks like you got the domain question correct. As for the rectangle question, consider the length of the altitude formed by the y-axis. That'll give you the y-intercept of the line AB, which, like the problem suggests, you should find the equation of. That'll give you the y-coordinate of the point in question and also an expression for the width of the triangle. You know the length already, so you can express the area of the rectangle as (length)(width).

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Originally Posted by s_cianci

It looks like you got the domain question correct. As for the rectangle question, consider the length of the altitude formed by the y-axis. That'll give you the y-intercept of the line AB, which, like the problem suggests, you should find the equation of. That'll give you the y-coordinate of the point in question and also an expression for the width of the triangle. You know the length already, so you can express the area of the rectangle as (length)(width).

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I'm not sure.. I got 1 for the altitude and then y=-x+1 for the equation.. is that right? How do I get the y coordinate? And this might be a dumb question but where is the width of a triangle? And how do I find the length of the rectangle/?

Since your equation is y = -x+1, that is the y-coordinate. The width of the rectangle is 2x. Now you're all set.