Ask Me Help Desk

Ask Me Help Desk (https://www.askmehelpdesk.com/forum.php)
-   Math & Sciences (https://www.askmehelpdesk.com/forumdisplay.php?f=402)
-   -   Geometry-parabola (https://www.askmehelpdesk.com/showthread.php?t=128076)

  • Sep 10, 2007, 03:42 PM
    spacefire5458
    geometry-parabola
    I don't understand the parabola definition and what is the algebraic equation?
    thank you:)
  • Sep 10, 2007, 04:11 PM
    tickle
    I can give you the parabola but you will have to fill out the algebraic equation yourself, which isn't all that difficult

    a parabola is a curve in the Cartesian plane defined by an irreducible equation of the form

    A x^2 + B xy + C y^2 + D x + E y + F = 0 \,

    such that B^2 = 4 AC \, where all of the coefficients are real, where A \not= 0 \, or C \not= 0 \, and where more than one solution, defining a pair of points (x, y) on the parabola, exists. That the equation is irreducible means it does not factor as a product of two not necessarily distinct linear equations.
  • Sep 10, 2007, 05:12 PM
    spacefire5458
    Is it y=4x^2?
  • Sep 11, 2007, 11:11 AM
    ebaines
    Quote:

    Originally Posted by spacefire5458
    Is it y=4x^2?

    y = 4x^2 is certainly a parabola.

    The general form for a parabola is:

    y = Ax^2 + Bx + C.

    Here if A >0, the parabola opens upward, and if A is negative it opens downward. For the example you gave y = 4x^2, the value of A is 4, B is 0 and C is 0. So this parabola opens upward.

    If you can convert this to the form y-k =a(x-h)^2, then the vertex is at the point (h,k). For the example case of y = 4x^2, this can convert to:
    y-0 = 4(x-0)^2, so this tells you the vertex is at (0,0).

  • All times are GMT -7. The time now is 08:50 AM.