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-   -   Algebra II (https://www.askmehelpdesk.com/showthread.php?t=126658)

  • Sep 6, 2007, 01:53 PM
    ahhhhh
    algebra II
    I really need help with alg II.:confused:

    problems :
    f(a) = 2a + 3
    f(x) = -x - 7
    f(h) = -6h - 2/3
    f(y) = -3y - 2
    f(d) = 1 - 4d
    f(x) = 5/6x + 1/2
    f(z) = z + 9.5
    f(x) = 2x - 3
    f(t) = 1/2t - 2
  • Sep 6, 2007, 01:55 PM
    ebaines
    What are you trying to do - draw a graph of each of these functions?
  • Sep 6, 2007, 02:11 PM
    ahhhhh
    Quote:

    Originally Posted by ebaines
    What are you trying to do - draw a graph of each of these functions?


    Err I don't really know
    It's the first time I've been in this class

    The directions are 'for each function, find f (-5)
  • Sep 6, 2007, 02:58 PM
    ebaines
    OK. I'll help you with the first problem, then maybe you can do the rest.

    The problem is: f(a) = 2a+3.

    A function is sort of like a machine, where you stick a number in for the independent variable (in this case, for "a"), "turn the crank," and out comes a second number for f(a). In this case you stick in a value for "a" and see what comes out. So, when they ask for f(-5), what they want is for you to stick -5 in place of the "a" and see what you get. What you have here is f(-5) = 2 x -5 + 3 = -7. So, f(-5) = -7.

    Now, can you do the rest?
  • Sep 8, 2007, 10:51 AM
    s_cianci
    Plug -5 into each variable and do the arithmetic.

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