Hi there
I could really use some help on this particular questions

Show that the particle moving with position equation x(t)=24t^2-3t^4 turns around after 2 seconds ( find values for position at t=0, t=1, t=2 and t=3 seconds and use a 0.01 second interval to show the velocity is 0 at t=2 seconds.)

I know how to find the values of the positions but not the velocity section

Thanks

The velocity is the rate of change of position. You know exactly how to do it, it's the same as the other one I showed you.

It wants you to show that at t=2 the sign of velocity changes from positive to negative.

Again, this is a very unintuitive way to lookat it, I think, but you have to live with what you're given :)

Hmmmm I see that I got lazy with the questions
Thanks again